Given an unsorted array of integers, find the length of longest continuous
increasing subsequence (subarray).
Input: [1,3,5,4,7] Output: 3 Explanation: The longest continuous increasing subsequence is [1,3,5], its length is 3. Even though [1,3,5,7] is also an increasing subsequence, it's not a continuous one where 5 and 7 are separated by 4.
Input: [2,2,2,2,2] Output: 1 Explanation: The longest continuous increasing subsequence is [2], its length is 1.
Note: Length of the array will not exceed 10,000.
implSolution{pubfnfind_length_of_lcis(nums:Vec<i32>) -> i32{letmut i = 0;letmut max_len = 0;for j in1..=nums.len(){if j == nums.len() || nums[j] <= nums[j - 1]{ max_len = max_len.max(j - i); i = j;}} max_len asi32}}